N^2-3=2N

Solution for N^2-3=2N equation:

Simplifying
N2 + -3 = 2N

Reorder the terms:
-3 + N2 = 2N

Solving
-3 + N2 = 2N

Solving for variable 'N'.

Reorder the terms:
-3 + -2N + N2 = 2N + -2N

Combine like terms: 2N + -2N = 0
-3 + -2N + N2 = 0

Factor a trinomial.
(-1 + -1N)(3 + -1N) = 0

Subproblem 1
Set the factor '(-1 + -1N)' equal to zero and attempt to solve:

Simplifying
-1 + -1N = 0

Solving
-1 + -1N = 0

Move all terms containing N to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1N = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1N = 0 + 1
-1N = 0 + 1

Combine like terms: 0 + 1 = 1
-1N = 1

Divide each side by '-1'.
N = -1

Simplifying
N = -1
Subproblem 2
Set the factor '(3 + -1N)' equal to zero and attempt to solve:

Simplifying
3 + -1N = 0

Solving
3 + -1N = 0

Move all terms containing N to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1N = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1N = 0 + -3
-1N = 0 + -3

Combine like terms: 0 + -3 = -3
-1N = -3

Divide each side by '-1'.
N = 3

Simplifying
N = 3
Solution
N = {-1, 3}